4.9t^2-11.9t-34=0

Solution for 4.9t^2-11.9t-34=0 equation:

4.9t^2-11.9t-34=0

a = 4.9; b = -11.9; c = -34;
Δ = b2-4ac
Δ = -11.92-4·4.9·(-34)
Δ = 808.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.9)-\sqrt{808.01}}{2*4.9}=\frac{11.9-\sqrt{808.01}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.9)+\sqrt{808.01}}{2*4.9}=\frac{11.9+\sqrt{808.01}}{9.8}
$